Walmart Labs Interview Question | Dice

Question

Let’s say you’re playing a dice game. You have 2 die. What’s the probability of rolling at least one 3?

in progress 0
Dhruv2301 55 years 4 Answers 826 views Great Grand Master 0

Answers ( 4 )

  1. Priyabrata017
    -1
    Reply

    Here there are two possibilities,
    Case 1: One die is rolled and it appears 3 and the other one in not three.
    Case 2. Both the die appear 3.

    The required probability = case1 or case 2
    = 1/6*5/6 + 1/6*1/6
    =6/36
    =1/6

  2. ravi_joe
    0
    Reply

    Each die has a 5/6 chance of avoiding a three, so a pair of dice would have a 5/6 x 5/6 = 25/36 chance of not rolling a three. From that we can conclude that there must be a 11/36 chance of getting at least one three

  3. swap007
    0
    Reply

    (1,3), (2,3),(4,3),(5,3),(6,3)
    (3,1), (3,2),(3,4),(3,5),(3,6)
    (3,3)
    Total = 11
    so probability of at least one three =
    11/36

  4. Ognish
    0
    Reply

    Sample space:
    (1,3), (2,3),(4,3),(5,3),(6,3)
    (3,1), (3,2),(3,4),(3,5),(3,6)
    (3,3)

    Total likely evebts= 11

    P robability of at least one three =
    11/36

Leave an answer

Browse
Browse